(-3v+1)(v^2-v-2)=0

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Solution for (-3v+1)(v^2-v-2)=0 equation: 


Simplifying
(-3v + 1)(v2 + -1v + -2) = 0

Reorder the terms:
(1 + -3v)(v2 + -1v + -2) = 0

Reorder the terms:
(1 + -3v)(-2 + -1v + v2) = 0

Multiply (1 + -3v) * (-2 + -1v + v2)
(1(-2 + -1v + v2) + -3v * (-2 + -1v + v2)) = 0
((-2 * 1 + -1v * 1 + v2 * 1) + -3v * (-2 + -1v + v2)) = 0
((-2 + -1v + 1v2) + -3v * (-2 + -1v + v2)) = 0
(-2 + -1v + 1v2 + (-2 * -3v + -1v * -3v + v2 * -3v)) = 0
(-2 + -1v + 1v2 + (6v + 3v2 + -3v3)) = 0

Reorder the terms:
(-2 + -1v + 6v + 1v2 + 3v2 + -3v3) = 0

Combine like terms: -1v + 6v = 5v
(-2 + 5v + 1v2 + 3v2 + -3v3) = 0

Combine like terms: 1v2 + 3v2 = 4v2
(-2 + 5v + 4v2 + -3v3) = 0

Solving
-2 + 5v + 4v2 + -3v3 = 0

Solving for variable 'v'.

The solution to this equation could not be determined.

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